Question 199906
I'm not sure what year you're going for, so I'm going to assume that you want to know the population in the year 2028.



You're off to a good start, the population equation is



{{{P=107.4(1.0143)^t}}} where t=0 is the year 2006 and P is the population in millions.



Since 2028-2006=22, this means that 22 years have passed since 2006 to get to 2028. So when the year is 2028, the value of "t" is {{{t=22}}}




{{{P=107.4(1.0143)^t}}} Start with the given equation.



{{{P=107.4(1.0143)^(22)}}} Plug in {{{t=22}}}



{{{P=107.4(1.367)}}} Raise 1.0143 to the 22nd power to get 1.367 



{{{P=146.816}}} Multiply



So in the year 2028, the population will be roughly 146.816 million people.



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If you're looking for the population in the year 2020, then...


Take note that 2020-2006=14. So {{{t=14}}} in the year 2020.



{{{P=107.4(1.0143)^t}}} Start with the given equation.



{{{P=107.4(1.0143)^(14)}}} Plug in {{{t=14}}}



{{{P=107.4(1.220)}}} Raise 1.0143 to the 14th power to get 1.220



{{{P=131.028}}} Multiply



So in the year 2020, the population will be roughly 131.028 million people.


If you round that value to the nearest tenth of a million, you get 131.0 million people.