Question 27637
First Number = X
Second Number = X+3
Som of Squares => {{{X^2 + (X+3)^2}}}
{{{X^2 + X^2 + 9 +6X}}}
{{{2X^2 + 9 +6X}}}
Given that this equals 149
{{{2X^2 + 9 +6X = 149}}}
Subtracting 149 on both sides
{{{2X^2 + 9 +6X - 149 = 0}}}
{{{2X^2 +6X - 140=0}}}

*[invoke quadratic "x", 2, 6, -140]

Since we are looking for Positive numbers X = 7
which means the second number is 10 :-)