Question 199618
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I already did this problem for you.  Question 199614.


http://www.algebra.com/algebra/homework/Rectangles/Rectangles.faq.question.199614.html


And again, I have to say that your triangle is NOT equilateral.  If it were equilateral, then all three sides would measure 16 and the height would be *[tex \Large 8\sqrt{3}].  But if the height is actually 12 as you say, the base must be *[tex \Large 8\sqrt{7}], so you have 2 equal sides and a third side that is a different measure so you have an isosceles triangle.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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