Question 27638
Consecutive integers = x, x+2, x+4


{{{x^2-(x+4)^2=80}}}
{{{x^2-(x^2+16+8x)=80}}}
{{{x^2-x^2+16+8x=80}}}
{{{16+8x=80}}}
8x=64
x=8


8+2=10
8+4=12



Hence, the 3 integers are 8, 10 and 12.
Paul.