Question 199808
1) Find the equation, in standard form, of the line perpendicular to 2x + 3y = -5 and passing through (3,-5). Write the equation in standard form, with all integer coefficients
:
slope of 2x+3y=5 is 3y=-2x+5--->y=(-2/3)x+5........-2/3
:
slope of line perpendicular to this line would be -3/2
:
now using point slope formula  y+5=-3/2(x-3)
:
y+5=-3/2x+9
:
2y+10=-3x+28
:
3x+2y=18(standard form)