Question 199813
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{x}{4}=\frac{x+8}{x}]


Cross multiply:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x^2 = 4x + 32]


Add *[tex \Large -4x - 32] to both sides:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x^2 - 4x - 32 = 0]


Now just factor the quadratic and use the Zero Product Rule.  Hint: *[tex \Large 4 \times -8 = - 32] and *[tex \Large 4 + (-8) = -4]



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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