Question 199801
{{{(z^(-8)x^8)/(x^(-8)z^0y^11)}}}
<pre><font size = 4 color = "indigo"><b>
First of all, any number to the 0 power
is just one so replace the {{{z^0}}} by {{{1}}}.

{{{(z^(-8)x^8)/(x^(-8)1y^11)}}}

which amounts to just erasing it:

{{{(z^(-8)x^8)/(x^(-8)y^11)}}}

Next we get rid of all negative exponents by this
pair of rules:

If any factor of the numerator has a negative exponent,
then move it from the numerator to the denominator and
change the sign of the exponent to positive:

If any factor of the denominator has a negative exponent,
then move it from the denominator to the numerator and
change the sign of the exponent to positive:

{{{(z^(-8)x^8)/(x^(-8)y^11)}}}

We move the {{{z^(-8)}}} from the numerator to the 
denominator and write it with a positive exponent
{{{z^8}}} in the denominator:

{{{(x^8)/(z^8x^(-8)y^11)}}}

Next we move the {{{x^(-8)}}} from the denominator to the 
numerator and write it with a positive exponent
{{{x^8}}} in the numerator:

{{{(x^8x^8)/(z^8y^11)}}}

Finally we add the exponents of {{{x}}} in the numerator
and we end up with:

{{{x^16/(z^8y^11)}}}

Edwin</pre>