Question 199807
Given {{{y = K*(x/z^2)}}}
Given {{{25 = K *(80/4^2)}}}
{{{25 = K *(80/16)}}}
{{{25 = K*5}}}
{{{5 = K}}}

{{{y = K*(x/z^2)}}}
{{{y = 5*(x/z^2)}}}
{{{y = 5*(52/2^2)}}}
{{{y = 5 *(52/4)}}}
{{{y = 5*13}}}
{{{y = 65}}}