Question 199696
(1)  {27(x^3y^4)^2 }/ [(3x)^2 y^-5]
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(27 x^6 y^8)/ 9x^2y^-5
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3 x^4 y^13
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(2)  { 2a* (4/3)b^2c)^(-3)} / (a^2bc^3)
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{ (8/3ab^2c)^(-3) } / (a^2bc^3)
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1/ { (8/3ab^2c)^3 } { a^2bc^3 }
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27 / { 512 a^3 b^6c^3} { a^2bc^3}
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27/(512 a^5 b^7 c^6)
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(3) { ( 9x^2y^6)^(1/2) } / { 3 (x^3y^9)^(1/3)
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(3xy^3) / 3 ( x y^3 ) =  1