Question 199777
Area of a parallelogram: 


Area = Base * Height ----> A = bh



{{{A=bh}}} Start with the given equation.



{{{A=(3x+2)(2x+3)}}} Plug in {{{b=3x+2}}} and {{{h=2x+3}}} (the given base and height)



{{{A=(3x)(2x)+(3x)(3)+(2)(2x)+(2)(3)}}} FOIL



{{{A=6x^2+9x+4x+6}}} Multiply



{{{A=6x^2+13x+6}}} Combine like terms.



So the trinomial for the area is {{{A(x)=6x^2+13x+6}}}



Now let's find A(3).



{{{A(x)=6x^2+13x+6}}} Start with the given equation.



{{{A(3)=6(3)^2+13(3)+6}}} Plug in {{{x=3}}}.



{{{A(3)=6(9)+13(3)+6}}} Square {{{3}}} to get {{{9}}}.



{{{A(3)=54+13(3)+6}}} Multiply {{{6}}} and {{{9}}} to get {{{54}}}.



{{{A(3)=54+39+6}}} Multiply {{{13}}} and {{{3}}} to get {{{39}}}.



{{{A(3)=99}}} Combine like terms.



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