<PRE><B>Question 199685</B>
the number of 3 person committees from a group of 10 is 10C3


groups of 2 women from a field of 4 is 4C2
groups of 1 men from a field of 6 is 6C1
so the number of 3 person groups with 2 women is (4C2)(6C1)


groups of 3 women from a field of 4 is 4C3


so the probability of at least 2 women in the group is [(4C2)(6C1) + 4C3] / 10C3</PRE>