Question 27590
f(x) = {{{x^3-5}}}


so, {{{y=x^3-5}}}
{{{y+5=x^3}}}
{{{(y+5)^(1/3)=x}}}


--> f(y) = {{{(y+5)^(1/3)}}}
or {{{f^(-1)(x) = (x+5)^(1/3)}}}



jon.