Question 199640


{{{(6x+7)^2=10}}} Start with the given equation.



{{{6x+7=""+-sqrt(10)}}} Take the square root of both sides.



{{{6x+7=sqrt(10)}}} or {{{6x+7=-sqrt(10)}}} Break up the "plus/minus" to form two equations.



{{{6x=-7+sqrt(10)}}} or {{{6x=-7-sqrt(10)}}} Subtract {{{7}}} from both sides.



{{{x=(-7+sqrt(10))/6}}} or {{{x=(-7-sqrt(10))/6}}} Divide both sides by 6.



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Answer:



So the solutions are {{{x=(-7+sqrt(10))/6}}} or {{{x=(-7-sqrt(10))/6}}}.