Question 195080
x^2 + 3x - 18 = 0
(x+6)(x-3)=0
x=-6  x=3
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<br>quadratic formula:
 -b plus or minus the square root of "b^2-4ac"
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                                       2a
x^2 + 3x - 18 = 0
<br>-3 plus or minus the square root of "(-3)^2-4(1)(-18)
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                         2(1)
<br>-3 plus or minus the square root of "9+72"
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                     2
<br>-3 plus or minus the square root of "81"
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                   2
<br>-3 plus or minus "9"
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          2
<br>the two equations you have:
-3+9                                    -3-9
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  2                                       2
<br>6                                    -12
-                                       ----
2                                        2
<br>3                                        -6
<br>
x={3,-6}