Question 199559
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The surface area of a rectangular solid is given by:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ A_s = 2lw + 2lh + 2wh]


Where *[tex \Large l] is the length, *[tex \Large w] is the width, and *[tex \Large h] is the height.


But we are given that *[tex \Large l = 2w], *[tex \Large h = 6w], and *[tex \Large A_s = 1000], so:



*[tex \LARGE \ \ \ \ \ \ \ \ \ \  2(2w)w + 2(2w)(6w) + 2w(6w) = 1000]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 4w^2 + 24w^2 + 12w^2 = 1000]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 40w^2 = 1000]


Solve for *[tex \Large w]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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