<PRE><B>Question 199572</B>


From {{{2x^2-3x+7}}} we can see that {{{a=2}}}, {{{b=-3}}}, and {{{c=7}}}



{{{D=b^2-4ac}}} Start with the discriminant formula.



{{{D=(-3)^2-4(2)(7)}}} Plug in {{{a=2}}}, {{{b=-3}}}, and {{{c=7}}}



{{{D=9-4(2)(7)}}} Square {{{-3}}} to get {{{9}}}



{{{D=9-56}}} Multiply {{{4(2)(7)}}} to get {{{(8)(7)=56}}}



{{{D=-47}}} Subtract {{{56}}} from {{{9}}} to get {{{-47}}}



Since the discriminant is less than zero, this means that there are two complex solutions.



In other words, there are no real solutions.
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