Question 199546
explain why a rational function can have a "hole". Give an exmple
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The rational function f(x) = [(x-2)(x+3)/(x-2)]
looks like the function g(x) = (x+3) but it has
a hole at x = 2 because f(x) has a domain which 
excludes x = 2.
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Cheers,
Stan H.