Question 199532


{{{20x+8y=32}}} Start with the given equation.



{{{8y=32-20x}}} Subtract {{{20x}}} from both sides.



{{{8y=-20x+32}}} Rearrange the terms.



{{{y=(-20x+32)/(8)}}} Divide both sides by {{{8}}} to isolate y.



{{{y=((-20)/(8))x+(32)/(8)}}} Break up the fraction.



{{{y=-(5/2)x+4}}} Reduce.



So the equation {{{y=-(5/2)x+4}}} is now in slope intercept form {{{y=mx+b}}} where the slope is {{{m=-5/2}}} and the y-intercept is {{{b=4}}}


note: the y-intercept is the point *[Tex \LARGE \left(0,4\right)]