Question 199262
Find 3 consecutive numbers such that twice the smallest is 23 more than the largest.
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1st: x-1
2nd: x
3rd: x+1
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Equation: 
2(x-1) = x+1 + 23
2x-2 = x + 24
x = 26 (2nd)
x-1= 25 (1st)
x+1=27 (3rd)
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Cheers,
Stan H.