Question 199243
{{{(a^2-3a)/(a-3)}}} Start with the given expression.



{{{(a(a-3))/(a-3)}}} Factor the numerator



{{{(a*highlight((a-3)))/highlight((a-3))}}} Highlight the common terms.



{{{(a*cross((a-3)))/cross((a-3))}}} Cancel out the common terms.



{{{a}}} Simplify



So {{{(a^2-3a)/(a-3)=a}}} where {{{a<>3}}}. So the statement is <i>always</i> true.



Note: "a" can be any complex number (it doesn't have to be rational)