<PRE><B>Question 199219</B>
A jar contains a total of 85 coins, all of which are either DIMES OR QUARTERS. If the coins together are worth $15.40, how many of each type of coin are in the jar? 
-----------------
D + Q = 85 (# of coins)
10D + 25Q = 1540 (value of coins)
D = 85-Q
Sub for D
10*(85-Q) + 25Q = 1540
850-10Q + 25Q = 1540
15Q = 690
Q = 46
D = 39
</PRE>