Question 199138
{{{x = -(2/3)y + 1}}}


Solve for y. Find the x-intercept, y intercept and slope 


Solving for y
{{{y  =  -(3/2)x + (3/2)}}}


To find the x-intercept, we set y = 0
Therefore, {{{x = -(2/3)y + 1}}} gives us x  = 1, and
x-intercept is: (1, 0)


To find the y-intercept, we set x = 0
Therefore, {{{y  =  -(3/2)x + (3/2)}}} gives us {{{y  =  (3/2)}}}, and 
y-intercept is:  (0, {{{3/2}}}), OR, 
just look at the equation in y = mx + b form, as “b” is the y-coordinate of the y-intercept. Therefore, from the equation, {{{y  =  -(3/2)x + (3/2)}}}, the y-intercept is: (0, {{{3/2}}}).


The equation, {{{y  =  -(3/2)x + (3/2)}}} is in y = mx + b form, and “m,” or 
-{{{3/2}}}, is the slope.