<PRE><B>Question 199163</B>
Big problem.
3 flavors, 40 total
L=lemon, C=cherry, O=orange
L=X, C=X(3), O=X(2)+4
X+3X+(2X+4)=total
6X+4=40
6X=40-4
6X=36
X=6
Therefore lemon=6, cherry=18, orange=16 ,=40 total

b)
first draw
lemon, 6/40 or 15%; cherry, 18/40 or 45%; orange, 16/40 or 40%
second draw
lemon, 5/39 or 13%; cherry, 17/39 or 44%; orange, 15/39 or 38%
sumation
draw the same twice
lemon, 2% chance; cherry, 20% chance; orange, 15% chance


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