Question 199148
Let x, x+2 & x+4 be the 3 even integers.
x(x+2)=5(x+4)-2
x^2+2x=5x+20-2
x^2+2x-5x-18=0
x^2-3x-18=0
(x-6)(x+3)=0
x-6=0
x=6 ans. for the first even integer.
6+2=8 for the second even integer.
6+4=10 for the third even integer.
Proof:
6*8=5*10-2
48=50-2
48=48