Question 199131
f(x)=x^3-x^2-2x
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To find the zeros, set f(x)=0 and solve for x:
0=x^3-x^2-2x
0=x(x^2-x-2)
0=x(x-2)(x+1)
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Setting each term (on the right) to zero we get:
x = {0,2,-1}