Question 199039
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Just to show a small illustration here where the two Cyclists are:
{{{drawing(200,200,-10,10,-1,1,arrow(-10,0,-8,0),arrow(10,0,8,0),locate(-9,.35,C[1]),locate(8,.35,C[2]),green(line(10,-.05,10,-.1)),green(line(-10,-.05,-10,-.1)),green(line(10,-0.075,-10,-0.075)),green(locate(-2,-.15,90miles)))}}}


We know Distance Formula = Speed x time


Both covered the Distance of 90miles in 2 hours:
{{{S[1]t+S[2]t=90mi}}}
*note: {{{S[1]=2S[2]}}}, Cyclist[1] is twice as fast Cyclist[2]


{{{highlight(2S[2])(2hrs)+S[2](2hrs)=90mi}}}
{{{4S[2]+2S[2]=90mi}}}
{{{6S[2]=90mi}}} ---> {{{cross(6)S[2]/cross(6)=cross(90)15mi/cross(6)}}}
{{{red(S[2]=15mph)}}}, Speed of {{{C[2]}}}


Also,
{{{S[1]=2S[2]=2*15}}}
{{{red(S[1]=30mph)}}}, Speed of {{{C[1]}}}


Check,
{{{S[1]t+S[2]t=90mi}}}
{{{30(2)+15(2)=90mi}}}
{{{60+30=90}}}
{{{90mi=90mi}}}


Thank you,
Jojo</font>