Question 199031
<font face="Garamond" size="+2">

*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \sum_{k=1}^n\,k^2 = \frac{n(n+1)(2n+1)}{6}=\frac{2n^3+3n^2+n}{6}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \sum_{k=1}^{50}\,k^2 =\frac{2(50)^3+3(50)^2+50}{6}]


You can do your own arithmetic.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
</font>