Question 198971
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Take the first derivative of your function, set it equal to zero, and solve the quadratic equation.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ f(x)=4x^3+x^2-0.06x+7]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ f'(x) = 12x^2 + 2x = 0.06]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 12x^2 + 2x - 0.06 = 0]


Solve for *[tex \Large x_1, x_2] using the quadratic formula to get your two *[tex \Large x]-coordinates.  Then evaluate *[tex \Large f(x_1)] and *[tex \Large f(x_2)] to get your two *[tex \Large y]-coordinates.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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