Question 198949
{{{log(10^x/x(x^2+5)(x^7+6))}}}
The 1st rule I will use is:
{{{log(a/b) = log(a) - log(b)}}}
{{{log(10^x/x(x^2+5)(x^7+6)) = log(10^x) - log(x(x^2+5)(x^7+6)) }}}
The next rule is:
{{{log(a^b) = b*log(a)}}}
{{{log(10^x) - log(x(x^2+5)(x^7+6)) = x*log(10) - log(x(x^2+5)(x^7+6)) }}}
The next rule is :
{{{log(a*b*c) = log(a) + log(b) + log(c)}}}
{{{x*log(10) - log(x(x^2+5)(x^7+6)) = x*log(10) - (log(x) + log(x^2 + 5)
+ log(x^7 + 6))}}}
Another rule is:
{{{log(10) = 1}}}
{{{x*log(10) - (log(x) + log(x^2 + 5) + log(x^7 + 6)) = 
x - log(x) - log(x^2 + 5) - log(x^7 + 6) }}} answer