Question 198945
Given Equations:
[1] 2x + 3y = 4
[2] x + 4y = 5

 2x + 3y = 4 ..........(1)
 x + 4y = 5 ...........(2)

Multiply Eq(1) by 1 and Eq(2) by 2:
 2x + 3y = 4
 2x + 8y = 10
Subtracting:
  - 5y = -6 ...........(3)

From Eq(3), we get:
 y = 6/5 ..............(4)

On Substituting value of y in Eq(1), we get:
 2x + 3*6/5 = 4
 x = 1/5 ..............(5)

Summary: 
 x = 1/5
 y = 6/5