Question 198859
To divide {{{(x^4-3x^3+x^2-x-15)/(x^2-x+2)}}}, we need to use polynomial long division



Polynomial Long Division:


<pre>
                       x^2 -2x - 3
        -----------------------------
x^2-x+2 ) x^4 - 3x^3 + x^2 - x - 15
          x^4 -  x^3 +2x^2
         -----------------
               -2x^3 - x^2 - x
               -2x^3 +2x^2 -4x 
               ---------------
                     -3x^2 +3x - 15
                     -3x^2 +3x -  6
                     --------------
                                 -9
</pre>


So {{{(x^4-3x^3+x^2-x-15)/(x^2-x+2)=x^2-2x-3-9/(x^2-x+2)}}} 



which also looks like



{{{(x^4-3x^3+x^2-x-15)/(x^2-x+2)=x^2-2x-3}}} remainder -9