Question 198858
First, sort the terms in the numerator to get: {{{3x^3+2x^2-11x-9}}}



So to divide {{{(3x^3+2x^2-11x-9)/(2x+5)}}}, we can use polynomial long division:


Polynomial Long Division:


<img src="http://i150.photobucket.com/albums/s91/jim_thompson5910/Algebra%20dot%20com/poly_div2.gif">



So {{{(3x^3+2x^2-11x-9)/(2x+5)=(3/2)x^2-(11/4)x+11/8-127/(8(2x+5))}}}



Or stated differently 



 {{{(3x^3+2x^2-11x-9)/(2x+5)=(3/2)x^2-(11/4)x+11/8}}} remainder {{{-127/8}}}