Question 198848
{{{(8y^4+12y^2-176)/(2y-4)}}} Start with the given expression.



{{{(4(y-2)(y+2)(2y^2+11))/(2y-4)}}} Factor the numerator



{{{(4(y-2)(y+2)(2y^2+11))/(2(y-2))}}} Factor the denominator



{{{(2*2(y-2)(y+2)(2y^2+11))/(2(y-2))}}} Factor 4 to get 2*2



{{{(cross(2)*2cross((y-2))(y+2)(2y^2+11))/(cross(2)cross((y-2)))}}} Cancel out the common terms.



{{{2(y+2)(2y^2+11)}}} Simplify



{{{4y^3+22y+8y^2+44}}} Expand and multiply



So {{{(8y^4+12y^2-176)/(2y-4)=4y^3+22y+8y^2+44}}} where {{{y<>2}}}