<PRE><B>Question 198841</B>


&lt;h4&gt;x-intercept&lt;/h4&gt;

To find the x-intercept, plug in {{{y=0}}} and solve for x



{{{3x+4y=-12}}} Start with the given equation.



{{{3x+4(0)=-12}}} Plug in {{{y=0}}}.



{{{3x+0=-12}}} Multiply {{{4}}} and 0 to get 0.



{{{3x=-12}}} Simplify.



{{{x=(-12)/(3)}}} Divide both sides by {{{3}}} to isolate {{{x}}}.



{{{x=-4}}} Reduce.



So the x-intercept is *[Tex \LARGE \left(-4,0\right)].



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&lt;h4&gt;y-intercept&lt;/h4&gt;

To find the y-intercept, plug in {{{x=0}}} and solve for y



{{{3x+4y=-12}}} Start with the given equation.



{{{3(0)+4y=-12}}} Plug in {{{x=0}}}.



{{{0+4y=-12}}} Multiply {{{3}}} and 0 to get 0.



{{{4y=-12}}} Simplify.



{{{y=(-12)/(4)}}} Divide both sides by {{{4}}} to isolate {{{y}}}.



{{{y=-3}}} Reduce.



So the y-intercept is *[Tex \LARGE \left(0,-3\right)].



Notice that if we graph the equation {{{3x+4y=-12}}}, we can see that the graph has the x-intercept *[Tex \LARGE \left(-4,0\right)] and the y-intercept *[Tex \LARGE \left(0,-3\right)]



{{{ drawing(500, 500, -5, 5, -5, 5,
grid(0),
graph(500, 500, -5, 5, -5, 5,(-12-3x)/(4))
)}}} Graph of {{{3x+4y=-12}}}
</PRE>