Question 198732
(3-2y) (5+4y)=0
15+12y-10y-8y^2=0
8y^2-2y-15=0
(4y+5)(2y-3)=0
4y+5=0
4y=-5
y=-5/4 ans.
2y-3=0
2y=3
y=3/2 ans.