Question 198689
{{{(w+x+y+z)/4=50}}} Start with the average equation. We'll make "z" the largest number.



{{{w+x+y+z=50*4}}} Multiply both sides by 5.



{{{w+x+y+z=200}}} Multiply



{{{z=200-w-x-y}}} Solve for "z"



{{{z=200-(w+x+y)}}}



So for "z" to be a maximum, the value of {{{w+x+y}}} must be a minimum. Since the integers are positive and the smallest positive integer is 1, this means that {{{w=x=y=1}}} which means that {{{w+x+y=3}}}. So....




{{{z=200-3=197}}}


This means that the largest integer is 197.