Question 198684
Well let's divide some numbers into 2 to see what possible remainders we get


0: 0/2 = 0 remainder 0

1: 1/2 = 0 remainder 1

2: 2/2 = 1 remainder 0

3: 3/2 = 1 remainder 1

4: 4/2 = 2 remainder 0

5: 5/2 = 2 remainder 1

6: 6/2 = 3 remainder 0


etc...


Starting to see the pattern? It turns out that if the dividend (ie the numerator) is even, then the remainder is 0. Otherwise, if the dividend is odd, then the remainder is 1. So the only possible choices of remainders are 0 and 1. These are the ONLY two possible choices.


So because 19 is odd, this means that the remainder of dividing 19 into 2 gets you a remainder of 1. 



So if you did the above work in a previous exercise, then you wouldn't have to do any dividing, but it helps see what's going on.