Question 198667
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ a^{\frac{1}{n}}\ =\ \small\sqrt[n]{\LARGE a}]


So


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 36^{\frac{1}{2}}\ =\ \sqrt{36}]



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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