Question 198563
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Yep, small error there.  Just move the fractions, i.e. the *[tex \LARGE \frac{4}{5}] and the *[tex \LARGE \frac{2}{3}], to the opposite sides of the equations, like this:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ A + 5 = \frac{4}{5}(B + 5)]


and


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ A - 5 = \frac{2}{3}(B - 5)]


Then follow the same solution process.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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