Question 198550
Applying "log rules":
log6(5-2a)-log6(3a)=1
log6(5-2a)/(3a)=1
(5-2a)/(3a)=6^1
(5-2a)/(3a)=6
5-2a=18a
5 = 20a
5/20 = a
1/4 = a