Question 198501
Find the equation of the axis of symmetry and the coordinates of the turning point for y=x^2+4x-3
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The vertex occurs when x = -b/2a = -4/2*1 = -2
The corresponding y-value is y = 2^2+(4*-2)-3 = -7
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Axis of symmetry is x = -2
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{{{graph(400,300,-10,10,-10,10,x^2+4x-3)}}}
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Cheers,
Stan H.