Question 198445
The units digit of a 2-digit number exceeds the tens digit by 3.
 If the number, increased by 2, is divided by the sum of the digits decreased
 by 3, the quotient is 6. Find the number.
:
two digits: x, y; the number: 10x + y
:
write an equation for each statement:
;
"The units digit of a 2-digit number exceeds the tens digit by 3."
y = x + 3
:
" If the number, increased by 2, is divided by the sum of the digits decreased
 by 3, the quotient is 6."
{{{((10x + y + 2))/((x + y - 3))}}} = 6
Replace y with (x+3)
{{{((10x + (x+3) + 2))/((x + (x+3) - 3))}}} = 6
Do the math
{{{((11x + 5))/((2x))}}} = 6
:
Multiply both sides by 2x
11x + 5 = 2x(6)
5 = 12x - 11x
x = 5
and
y = 5 + 3
y = 8
:
The number: 58
:
;
Check solution in the statement:
"If the number, increased by 2, is divided by the sum of the digits decreased
 by 3, the quotient is 6."
{{{((58 + 2))/((5 + 8 - 3))}}} = 6