Question 198369
{{{f(x)=(x-7)/(4x+8)}}}
{{{f^-1(x)}}}=?
{{{y=(x-7)/(4x+8)}}}
Invert
{{{x=(y-7)/(4y+8)}}}
Solve for y
{{{x(4y+8)=y-7}}}
{{{4xy+8x=y-7}}}
{{{4xy-y=-8x-7}}}
{{{y(4x-1)=-8x-7}}}
{{{y=(-8x-7)/(4x-1)}}}
So
If {{{f(x)=(x-7)/(4x+8)}}}
Then {{{f^-1(x)=(-8x-7)/(4x-1)}}}