Question 198356
{{{f(x)=sqrt(8x)+2}}}
{{{f^-1(x)}}}=?
{{{y=sqrt(8x)+2}}}
Invert
{{{x=sqrt(8y)+2}}}
Solve for y
{{{x+2=sqrt(8y)}}}
{{{8y=(x+2)^2}}}
{{{y=((x+2)^2)/8)}}}
So
If {{{f(x)=sqrt(8x)+2}}}
Then {{{f^-1(x)=((x+2)^2)/8}}}