Question 198274
ln(x^2+10)>ln(x)+ln(7)
e^ln(x^2+10)>e^ln(7x)
x^2+10>7x
x^2-7x+10=0 Use an equal sign instead of inequality.
(x-5)(x-2)=0
x=5, x=2 These are inflection points.
Since the coefficient of x^2 is positive (+1) the graph has a minimum and the equation is negative when 5>x>2
.
Ed
.
{{{graph(500,500,-10,10,-10,10,x^2-7x+10)}}}