Question 198216
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Let <b><i>x</i></b> represent the smaller number and <b><i>y</i></b> represent the larger, then:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x + y = 33]


and


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y = x + 3]


so

*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x + x + 3 = 33]


Just solve for *[tex \LARGE x]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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