<PRE><B>Question 198180</B>
A(t) = Ao 2^(-t/5760) 
A= amount of carbon 14 that a specimen contains
A= original amount of carbon 14
t=time in years
5760= half life of carbon-14
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A specimen that originally contained 120 milligrams of carbon-1 now contains 100 milligrams of this substance, what is the age of the specimen, to the nearest hundred years?
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100 = 120*2^(-t/5760)
(5/6) = 2^(-t/576)0
Take the log to get:
(-t/5760)log(2) = log(5/6)
-t/5760 = -0.263034
t = 1515.078 year
t = 1500 years when rounded to the nearest 100
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Cheers,
Stan H. 
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