Question 198064
<font face="Garamond" size="+2">


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ A + B + C = 180]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ A = 3B]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ B + C = 90 \ \ \Rightarrow\ \ C = 90 - B]


So, by substitution:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 3B + B + (90 - B) = 180]


Solve for B and the rest will follow easily.



John
*[tex \LARGE e^{i\pi} + 1 = 0]
</font>