Question 198032
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Step 1.  Put your equation into slope-intercept form by solving for *[tex \LARGE y] in terms of *[tex \LARGE x], i.e. make it look like:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y = mx + b]


Step 2.  Determine the slope of the given line by inspection of the coefficient on *[tex \LARGE x] in the result from step 1.


Step 3.  Use:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  L_1 \perp L_2 \ \ \Leftrightarrow\ \ m_1 = -\frac{1}{m_2} \text{ and } m_1, m_2 \neq 0]


to determine the slope of the desired line, i.e. find the negative reciprocal of the slope determined in step 2.


Step 4.  Create the equation of the desired line by use of the point-slope form of the equation of a line:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y - y_1 = m(x - x_1) ]


where *[tex \LARGE m] is the slope calculated in step 3, and *[tex \Large (x_1,y_1)] is the given point.


Step 5.  Arrange the equation into the form required by your assignment or instructor's instructions.  However, since the question states "find <b><i>an</i></b> equation..." the result of step 4 is just as valid as any other form of the equation.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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