Question 197923
There are 220 barrels of cement in one shed and 510 barrels in another. How many barrels must be transferred from the second to the first shed will contain two thirds as much as the second?
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Let x = number of barrels transferred
then
220 + x = (2/3)(510-x)
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Now, solve for x:
220 + x = (2/3)(510-x)
Multiply both sides by 3:
660 + 3x = (2)(510-x)
660 + 3x = 1020 - 2x
660 + 5x = 1020
5x = 360
x = 72 barrels